A) \[F\to {{F}^{-}}\]
B) \[Cl\to C{{l}^{-}}\]
C) \[O\to {{O}^{2-}}\]
D) \[H\to {{H}^{-}}\]
Correct Answer: C
Solution :
The second I.E. is greater than first I.E. similarly second E.A. is greater than first E.A. the energy is to be supplied to force the second \[{{e}^{-}}\] into the anion.
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