A) One \[\alpha \]-particle
B) One \[\beta \]-particle
C) One \[\alpha \] and two \[\beta \]-particles
D) One \[\beta \] and two \[\alpha \]- particles
Correct Answer: C
Solution :
\[_{z}{{A}^{m}}{{\to }_{Z}}{{B}^{m-4}}{{+}_{2}}H{{e}^{4}}+{{2}_{-1}}{{e}^{o}}\]You need to login to perform this action.
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