A) \[4\alpha ,\,7\beta \]
B) \[6\alpha ,\,4\beta \]
C) \[7\alpha ,\,4\beta \]
D) \[10\alpha ,\,8\beta \]
Correct Answer: C
Solution :
\[_{92}{{U}^{235}}\to {{\,}_{82}}P{{b}^{207}}+x{{\,}_{2}}H{{e}^{4}}+y{{\,}_{-1}}{{\beta }^{0}}\] no. of a-particles = \[\frac{235-207}{4}=\frac{28}{4}=7\alpha \] no. of \[\beta \]-particles = \[92-82-2\times 7=4\beta \].
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