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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and  \[g=10\,m/{{s}^{2}}\], the body will stop after covering a distance of                                     [MP PMT 1999]              

    A)                         10 m               

    B)                         25 m            

    C)                         50 m               

    D)                         250 m

    Correct Answer: B

    Solution :

                                \[S=\frac{{{u}^{2}}}{2\mu g}=\frac{{{(10)}^{2}}}{2\times 0.2\times 10}=25\ m\]            


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