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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A body of 10 kg is acted by a force of 129.4 N if \[g=9.8\,m/{{\sec }^{2}}\]. The acceleration of the block is  \[10\,m/{{s}^{2}}\]. What is the coefficient of kinetic friction          [EAMCET 1994]

    A)                         0.03                

    B)                         0.01            

    C)                         0.30                

    D)                         0.25

    Correct Answer: C

    Solution :

                                Net force on the body = Applied force ? Friction             \[ma=F-{{\mu }_{k}}mg\]Þ\[{{\mu }_{k}}=\frac{F-ma}{mg}=\frac{129.4-10\times 10}{10\times 9.8}=0.3\]            


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