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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is \[[g=10\,m{{s}^{-2}}]\]                                                             [CBSE  PMT 1992]            

    A)                         30 m               

    B)                         40 m            

    C)                         72 m               

    D)                         20 m

    Correct Answer: B

    Solution :

                                \[s=\frac{{{u}^{2}}}{2\mu \ g}=\frac{{{(20)}^{2}}}{2\times 0.5\times 10}=40\ m\]            


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