JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A block of mass 50 kg slides over a horizontal distance of 1 m.  If the coefficient of friction between their surfaces is 0.2, then work done against friction is [BHU 2001; CBSE PMT 1999, 2000; AIIMS 2000]

    A)             98 J    

    B)               72J

    C)             56 J    

    D)             34 J

    Correct Answer: A

    Solution :

                    \[W=\mu mgS=0.2\times 50\times 9.8\times 1=98\ J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner