A) \[9.8\,m/{{s}^{2}}\]
B) \[10\,m/{{s}^{2}}\]
C) \[12.6\,m/{{s}^{2}}\]
D) \[19.6\,m/{{s}^{2}}\]
Correct Answer: B
Solution :
From the relation \[F-\mu mg=ma\] \[a=\frac{F-\mu mg}{m}=\frac{129.4-0.3\times 10\times 9.8}{10}=10\ m/{{s}^{2}}\]
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