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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Kinetic Friction

  • question_answer
    A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is             \[(J=4.2\,joule/cal\] and \[g=9.8\,m/{{s}^{2}})\]                                                 [MH CET (Med.) 2001]            

    A)                         9.33 cal                       

    B)                         10.21 cal            

    C)                         12.67 cal                     

    D)                           13.34 cal

    Correct Answer: A

    Solution :

                                Work done = Force × Displacement\[=\mu \ mg\times (v\times t)\] \[W=(0.2)\times 2\times 9.8\times 2\times 5\ joule\]             Heat generated Q\[=\frac{W}{J}\]\[=\frac{0.2\times 2\times 9.8\times 2\times 5}{4.2}\]\[=9.33\]cal            


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