Answer:
From kinetic theory, \[P=\frac{1}{3}\frac{M}{V}\overline{{{\upsilon }^{2}}}\] But \[\overline{{{\upsilon }^{2}}}\propto T\] \[\therefore \] \[P\propto \frac{MT}{V}\] As both T and V remain unchanged but mass M is doubled, so the pressure of mixture gets doubled i.e., it is equal to 2P.
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