Answer:
Number of moles in \[32g\] of \[{{O}_{2}}=1\] \[\therefore \]Number of moles in \[\text{16 g}\] of \[{{\text{O}}_{2}}=\frac{1}{32}\times 16=\frac{1}{2}\] As \[\text{PV}=\text{nRT}\] and \[n=1/2,\],so \[PV=\frac{1}{2}RT.\]
You need to login to perform this action.
You will be redirected in
3 sec