question_answer

A particle of mass 0.3 kg is subjected to a force of \[F=-kx\]with\[k=15N{{m}^{-1}}\]. What will be its initial acceleration, if it is released from a point 20 cm away from the origin?                   

Answer:

                 Here \[k=15N{{m}^{-1}},\] \[x=20cm=0.20m,m=0.3kg\] \[F=-kx=15\times 0.20=-3N\] Acceleration,     \[a=\frac{F}{m}=\frac{-3}{0.3}=-10\,m{{s}^{-2}}.\]