A) \[\text{3}0.\text{7}{}^\circ \]
B) \[\text{35}.\text{3}{}^\circ \]
C) \[\text{41}.\text{7}{}^\circ \]
D) \[\text{48}.\text{6}{}^\circ \]
Correct Answer: D
Solution :
As per the given figure on pg. 16, \[{{n}_{i}}\sin i={{n}_{r}}\sin r,(1.3)\sin {{60}^{o}}=(1.5)\sin (r)\] \[\frac{13}{10}\times \frac{\sqrt{3}}{2}=\frac{3}{2}=\sin r,\sin r=0.577,r={{48.6}^{o}}\]You need to login to perform this action.
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