A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) zero
Correct Answer: D
Solution :
First we will calculate \[{{\delta }_{m}}\] for the given prism. \[\therefore \] \[\sqrt{2}=\frac{\sin (60+{{\delta }_{m}})/2}{\sin 30}\] \[\Rightarrow \] \[{{\delta }_{m}}\mathbf{=3}{{\mathbf{0}}^{\mathbf{o}}}\] It means that the given case is of minimum deviation. We know that in the position of minimum deviation, the refracted ray is parallel to the base of prism.You need to login to perform this action.
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