A) \[45{}^\circ \]
B) \[60{}^\circ \]
C) \[37{}^\circ \]
D) \[72{}^\circ \]
Correct Answer: B
Solution :
For the position of\[{{\delta }_{m}},\,\,r=\frac{A}{2}={{30}^{o}}\] Now, \[\mu =\frac{\sin i}{\sin r}=\frac{\sin i}{\sin A/2}\] \[\therefore \] \[\sqrt{3}=\frac{\sin i}{1/2}\] \[\Rightarrow \] \[i=60\]. \[\therefore \] \[{{\delta }_{m}}=2i-A=120-60=60\]
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