A) 1.80,0.625
B) 0554,0.625
C) 1.80, 1.6
D) 0.554,1.6
Correct Answer: A
Solution :
Given:\[{{\mu }_{w}}=1\times 33,\,\,{{\mu }_{g}}=1.5\]and\[{{\mu }_{0}}=2\times 40\] Now, \[_{w}{{\mu }_{D}}=\frac{{{\mu }_{D}}}{{{\mu }_{w}}}=\frac{2\cdot 40}{1\cdot 33}=1.80\] Further \[_{D}{{\mu }_{g}}=\frac{{{\mu }_{g}}}{{{\mu }_{D}}}=\frac{1\cdot 50}{2\cdot 40}\mathbf{=0}\mathbf{.265}\]
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