A) \[4x+8y+7z=41\]
B) \[4x-8y+7z=41\]
C) \[4x-8y-7z=41\]
D) \[4x-8y+7z=39\]
Correct Answer: B
Solution :
Any plane through given line is \[A(x-1)+B(y+2)+C(z-3)=0\] .....(i) and \[5A+6B+4C=0\] ?..(ii) Since, plane (i) passes through (4, 3, 7), we get \[3A+5B+4C=0\] .....(iii) Solving (ii) and (iii), we get \[\frac{A}{4}=\frac{B}{-8}=\frac{C}{7}\] \[\therefore \] Equation of required plane is \[4x-8y+7z=41\].You need to login to perform this action.
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