A) (3, ?1, 1)
B) (3, 1, 1)
C) (1, 1, 3)
D) (1, 3, 1)
Correct Answer: A
Solution :
Let point be (a, b, c), then \[2a+4b-c=1\] .....(i) and \[a=2k+1,\,\,b=-3k+2\] and \[c=4k-3\], (where k is constant) Substituting these values in (i), we get \[2\,(2k+1)+4\,(-3k+2)-(4k-3)=1\,\,\Rightarrow \,\,k=1\] Hence required point is (3, ?1, 1). Trick : The point must satisfy the lines and plane. Obviously (3, ? 1, 1) satisfies.You need to login to perform this action.
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