A) (3, 1, ?2)
B) (3, ? 2, 1)
C) (2, ?1, 3)
D) (?1, ?2, ?3)
Correct Answer: B
Solution :
Line is \[\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}=\lambda \,\](Let) \[x=3\lambda -3;\,\,y=-2\lambda +2;\,\,z=\lambda -1\]line intersects plane, therefore,\[4(3\lambda -3)+5(-2\lambda +2)+3(\lambda -1)-5=0\]\[\,\,\Rightarrow \lambda =2\]. So, \[x=3;\,\,y=-2;\,\,z=1\]. Trick : Since the point (3, ? 2, 1) satisfies both the equations.You need to login to perform this action.
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