A) 132 minutes
B) 108 minutes
C) 92 minutes
D) 84 minutes
Correct Answer: D
Solution :
(d): Let the time taken by Subodh in going from Dwarka to dhaula kuan be \[{{t}_{1}}\] minutes and the time taken by Sudheer in going from R.K. Puram to Dhaula Kuan be \[{{t}_{2}}\] minutes \[\therefore \] The new speed of Subodh in returning is 66.666% of his original speed, Hence time spent in returning \[=\frac{3}{2}{{t}_{1}}\therefore {{t}_{1}}+\frac{3}{2}{{t}_{1}}=120\Rightarrow {{t}_{1}}=48\] However, \[{{t}_{1}}={{t}_{2}}\]also, speed of Sudheer in returning is \[\frac{4}{3}\] times his original speed. \[\therefore \] time taken for Sudheer to return \[=\frac{3}{4}{{t}_{2}}\]. Thus, Sudheer?s total time is \[{{t}_{2}}+\frac{3}{4}{{t}_{2}}=48+36=84\]minutes.
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