A) 100
B) 10
C) 20
D) 200
Correct Answer: B
Solution :
(b): Let the positive number be x. Then, according to the question \[x+10=\frac{200}{x}~\Rightarrow {{x}^{2}}+10x=200\] \[\Rightarrow {{x}^{2}}+10x-200=0\Rightarrow (x-10)(x+20)=0\] \[\therefore x=10,-20,\]since x is a positive number. So, the required number is 10.You need to login to perform this action.
You will be redirected in
3 sec