A) \[2r=s+t\]
B) \[2t=r+s\]
C) \[2s=r+t\]
D) \[r+s+t=0\]
Correct Answer: C
Solution :
(c): Put (p, p) in both eqns. \[\Rightarrow ap+bp=(s-t)\] and, \[bp+ap=(r-s)\Rightarrow (s-t)=(r-s)\Rightarrow 2s=r+t\]You need to login to perform this action.
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