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8th Class Mathematics Linear Equations in One Variable Question Bank Linear equations in One Variable

  • question_answer
    Solve for x: \[\frac{(3x+1)}{16}+\frac{(2x-3)}{7}=\frac{(x+3)}{8}+\frac{(3x-1)}{14}\]

    A)  5                                

    B)  \[10\]

    C) \[-14\] 

    D)        \[12\]

    Correct Answer: A

    Solution :

    We have, \[\frac{(3x+1)}{16}+\frac{(2x-3)}{7}=\frac{(x+3)}{8}+\frac{(3x-1)}{14}\] \[\Rightarrow \frac{7(3x+1)+16(2x-3)}{112}\]                         \[=\frac{14(x+3)+8(3x-1)}{112}\] \[\Rightarrow \frac{21x+7+32x-48}{112}=\frac{14x+42+24x-8}{112}\] \[\Rightarrow \frac{53x-41}{112}=\frac{38x+34}{112}\] \[\Rightarrow 53x-41=38x+34\Rightarrow 15x=75\] \[\Rightarrow x=\frac{75}{15}=5\]


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