A) 3200
B) 2400
C) 4000
D) 4800
Correct Answer: D
Solution :
(d): Let total sweets be 'n? Students were supplied to get 'x' sweets \[160x=n\] But actually \[120\left( x+10 \right)=n\] \[\Rightarrow \frac{120}{160}n=\frac{3}{4}n\] \[\Rightarrow \frac{3n}{4}+1200=n\] \[n=4800.\]You need to login to perform this action.
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