A) \[~y=(90{}^\circ +x)\]
B) \[~y=(90{}^\circ -x)\]
C) \[~y=(180{}^\circ -x)\]
D) \[~y=\left( x+180{}^\circ \right)\]
Correct Answer: B
Solution :
We have give, \[\angle A+\angle B={{90}^{o}}\] \[\Rightarrow \]\[x+y={{90}^{o}}\Rightarrow y=({{90}^{o}}-x)\]You need to login to perform this action.
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