8th Class Mathematics Related to Competitive Exam Question Bank Logarithms

  • question_answer
    log 160 is equal to:

    A)  \[2\,\text{log}\,2+3\,\text{log}\,3\]         

    B)  \[~3\,\text{log}\,2+2\,\text{log}\,3\]

    C)  \[3\,\text{log}2+2\,\text{log}\,3-\text{log}\,5\]

    D)  \[5\,\text{log}\,2+\text{log}\,5\]

    Correct Answer: D

    Solution :

    (d): \[160=2\times 2\times 2\times 2\times 2\times 5\] So, So, \[log160=log\left( {{2}^{5}}\times 5 \right)=log{{2}^{5}}+log5\] \[51og2+log5\]


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