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8th Class Mathematics Related to Competitive Exam Question Bank Logarithms

  • question_answer
    If \[\mathbf{lo}{{\mathbf{g}}_{\mathbf{8}}}\mathbf{x+lo}{{\mathbf{g}}_{\mathbf{8}}}\frac{\mathbf{1}}{\mathbf{6}}\mathbf{=}\frac{\mathbf{1}}{\mathbf{3}}\mathbf{,}\] then the value of x is:

    A)  12    

    B)  16

    C)  18                               

    D)  24

    Correct Answer: A

    Solution :

    (a): \[{{\log }_{8}}\frac{x}{6}=\frac{1}{3}\] =\[\frac{x}{6}={{(8)}^{\frac{1}{3}}}\] \[\frac{x}{6}=2\] \[x=12\]         


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