A) \[-\left( 1+x \right)\]
B) \[{{\left( 1+x \right)}^{-1}}\]
C) \[\frac{a}{10}\]
D) \[\frac{1}{10a}\]
Correct Answer: A
Solution :
(a): \[\text{log}\left( \frac{1}{80} \right)=\text{lo}{{\text{g}}_{10}}1-\text{log}\,80\] \[=-\,\text{lo}{{\text{g}}_{10}}\left( 8\times 10 \right)=-({{\log }_{10}}8+{{\log }_{10}}10)=-(x+1).\]
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