A) 1 N
B) \[\frac{{{10}^{-7}}}{4\pi }N\]
C) \[{{10}^{-7\,}}\,N\]
D) \[4\pi \times {{10}^{-7}}N\]
Correct Answer: C
Solution :
\[F={{10}^{-7}}\times \frac{{{m}^{2}}}{{{r}^{2}}}=\frac{{{10}^{-7}}{{\left( 1 \right)}^{2}}}{{{\left( 1 \right)}^{2}}}={{10}^{-7}}N\]You need to login to perform this action.
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