A) \[4\,V\]
B) \[2\,V\]
C) \[\frac{V}{2}\]
D) \[\frac{V}{4}\]
Correct Answer: D
Solution :
Magnetic potential at a distance d from the bar magnet on it's axial line is given by \[V=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{{{d}^{2}}}\] Þ \[V\propto M\] Þ \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{M}_{1}}}{{{M}_{2}}}\] Þ \[\frac{V}{{{V}_{2}}}=\frac{M}{M/4}\] Þ \[{{V}_{2}}=\frac{V}{4}\]You need to login to perform this action.
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