A) \[1/2\]
B) \[2\]
C) \[4\]
D) \[1/4\]
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\Rightarrow T\propto \frac{1}{\sqrt{M}}\Rightarrow \frac{{{M}_{A}}}{{{M}_{B}}}={{\left( \frac{{{T}_{B}}}{{{T}_{A}}} \right)}^{2}}=\frac{4}{1}\]
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