A) \[\frac{n}{2\sqrt{2}}\]
B) \[\frac{n}{\sqrt{2}}\]
C) \[2\sqrt{2}n\]
D) \[\sqrt{2}n\]
Correct Answer: C
Solution :
No. of oscillation per minute \[=\frac{1}{2\pi }\sqrt{\frac{M{{B}_{H}}}{I}}\] \[\begin{align} & \Rightarrow n\propto \sqrt{M{{B}_{H}}};\ \ M\to 4\ times \\ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {{B}_{H}}\to 2\ times \\ \end{align}\] So \[\nu \to \sqrt{8}\ times\ i.e.\ {\nu }'=\sqrt{8}\nu =2\sqrt{2}n\]
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