A) 9 : 4
B) 3 : 2
C) 4 : 9
D) 2 : 3
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{I}{MH}}\Rightarrow T\propto \frac{1}{\sqrt{H}}\]Þ \[\frac{{{T}_{A}}}{{{T}_{B}}}=\sqrt{\frac{{{H}_{B}}}{{{H}_{A}}}}\] Þ \[\frac{{{H}_{A}}}{{{H}_{B}}}=\]\[{{\left( \frac{{{T}_{B}}}{{{T}_{A}}} \right)}^{2}}={{\left( \frac{3}{2} \right)}^{2}}=\frac{9}{4}\].
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