A) \[\frac{1}{3}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{\sqrt{3}}\]
D) \[\sqrt{3}\]
Correct Answer: C
Solution :
\[{{T}_{Sum}}=2\pi \sqrt{\frac{({{I}_{1}}+{{I}_{2}})}{({{M}_{1}}+{{M}_{2}}){{B}_{H}}}}\] \[{{T}_{diff}}=2\pi \sqrt{\frac{{{I}_{1}}+{{I}_{2}}}{({{M}_{1}}-{{M}_{2}}){{B}_{H}}}}\] \[\Rightarrow \frac{{{T}_{s}}}{{{T}_{d}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{M}_{1}}-{{M}_{2}}}{{{M}_{1}}+{{M}_{2}}}}=\sqrt{\frac{2M-M}{2M+M}}=\frac{1}{\sqrt{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
