A) \[\frac{T}{\sqrt{2}}\]
B) \[T\]
C) \[\sqrt{2}T\]
D) \[2T\]
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{I}{MB}}\Rightarrow \frac{T}{{{T}'}}=\sqrt{\frac{{{B}'}}{B}}=\sqrt{\frac{B}{{{B}_{H}}}}\] \[\Rightarrow \frac{T}{{{T}'}}=\sqrt{\frac{1}{\cos \varphi }}=\sqrt{\frac{1}{\cos {{60}^{o}}}}=\sqrt{2}\]\[\Rightarrow {T}'=\frac{T}{\sqrt{2}}\]
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