JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

  • question_answer
    A bar magnet has a magnetic moment equal to\[5\times {{10}^{-5}}weber\times m.\] It is suspended in a magnetic field which has a magnetic induction  equal to \[8\pi \times {{10}^{-4}}tesla.\] The magnet vibrates with a period of vibration equal to 15 sec. The moment of inertia of the magnet is [MP PMT 1993; CBSE PMT 2001]

    A)            \[22.5kg\times {{m}^{2}}\]    

    B)            \[11.25\times kg\times {{m}^{2}}\]

    C)            \[5.62\times kg\times {{m}^{2}}\]                                  

    D)            \[7.16\times {{10}^{-7}}kg-{{m}^{2}}\]

    Correct Answer: D

    Solution :

               Time period of a magnet \[T=2\pi \sqrt{\frac{I}{MB}}\] or \[I=\frac{{{T}^{2}}MB}{4{{\pi }^{2}}}=\frac{225\times 5\times {{10}^{-5}}\times 8\pi \times {{10}^{-4}}}{4{{\pi }^{2}}}\] \[\therefore \ I=7.16\times {{10}^{-7}}kg-{{m}^{2}}\]


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