A) \[\frac{{{T}_{0}}}{2}\]
B) \[\frac{{{T}_{0}}}{\sqrt{2}}\]
C) \[\sqrt{2}{{T}_{0}}\]
D) \[2{{T}_{0}}\]
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\Rightarrow T\propto \sqrt{I}\propto \sqrt{\text{w}}\Rightarrow {T}'=\sqrt{2}\ {{T}_{0}}\]
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