A) 0o
B) 30o
C) 45o
D) 60o
Correct Answer: C
Solution :
In case of tangent galvanometer as \[i=k\tan \varphi \] Differentiating both side w.r.t. \[\varphi \] \[\frac{di}{d\varphi }=k{{\sec }^{2}}\varphi \Rightarrow di=k{{\sec }^{2}}d\varphi \] \[\Rightarrow \frac{di}{i}=\frac{d\varphi }{\sin \varphi \cos \varphi }=\frac{2d\varphi }{\sin 2\varphi }\] Hence the error in the measurement will be least when \[\sin 2\varphi =\max =1\]\[\Rightarrow 2\varphi ={{90}^{o}}\Rightarrow \varphi ={{45}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
