A) 1 amp
B) \[2\sqrt{3}\,amp\]
C) 4 amp
D) 6 amp
Correct Answer: D
Solution :
\[i\propto \tan \varphi \Rightarrow \frac{{{i}_{1}}}{{{i}_{2}}}=\frac{\tan {{\varphi }_{1}}}{\tan {{\varphi }_{2}}}\] \[\Rightarrow \frac{2}{{{i}_{2}}}=\frac{\tan 30}{\tan 60}\Rightarrow {{i}_{2}}=6\ amp\]
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