A) 1.96 ´ 10?4 T
B) 1.96 ´ 10?5 T
C) 1.96 ´ 104 T
D) 1.96 ´ 105 T
Correct Answer: B
Solution :
\[B={{B}_{H}}\tan \theta \]\[=0.34\times {{10}^{-4}}\tan 30{}^\circ =1.96\times {{10}^{-5}}T\]
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