A) 4 T
B) 2 T
C) T
D) T/2
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{I}{M\ {{B}_{H}}}}\]; where \[I=\frac{\text{w}({{L}^{2}}+{{b}^{2}})}{12}\] (w =Mass of magnet) \[\Rightarrow T\propto \sqrt{W},\]If \[\text{w}\to \]four times then \[T\to \]Two times
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