A) 4 : 9
B) 9 : 4
C) 2 : 3
D) 3 : 2
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{1}{M{{B}_{H}}}}\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] \[\Rightarrow \frac{{{M}_{1}}}{{{M}_{2}}}=\frac{T_{2}^{2}}{T_{1}^{2}}=\frac{{{\left( 60/15 \right)}^{2}}}{{{\left( 60/10 \right)}^{2}}}=\frac{4}{9}\]
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