A) 2 s
B) 2/3 s
C) \[2\sqrt{3}\,s\]
D) \[2/\sqrt{3}\,s\]
Correct Answer: B
Solution :
Initially, the time period of the magnet \[T=2=2\pi \sqrt{\frac{I}{MB}}\] ..... (i) For each part, it?s moment of inertia \[=\frac{I}{27}\]and magnetic moment \[=\frac{M}{3}\] \[\therefore \] Moment of inertia of system \[{{I}_{s}}=\frac{I}{27}\times 3=\frac{I}{9}\] Magnetic moment of system \[{{M}_{s}}=\frac{M}{3}\times 3=M\] Time period of system \[{{T}_{s}}=2\pi \sqrt{\frac{{{I}_{s}}}{{{M}_{s}}B}}=\frac{1}{3}\times 2\pi \sqrt{\frac{I}{MB}}=\frac{T}{3}=\frac{2}{3}\sec \]
You need to login to perform this action.
You will be redirected in
3 sec
