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JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

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    The radius of the coil of a Tangent galvanometer. which has 10 turns is 0.1m. The current required to produce a deflection of 60° \[({{B}_{H}}=4\times {{10}^{-5}}T)\] is    [MP PET  2005]

    A)          3 A

    B)          1.1 A                             

    C)          2.1 A                             

    D)          1.5 A

    Correct Answer: B

    Solution :

               \[B={{B}_{H}}\tan \theta \] Þ \[\frac{{{\mu }_{0}}ni}{2r}={{B}_{H}}\tan \theta \]                    Þ \[i=\frac{2r.\ {{B}_{H}}\tan \theta }{{{\mu }_{0}}n}\]\[=\frac{2\times 0.1\times 4\times {{10}^{-5}}}{10\times 4\pi \times {{10}^{-7}}}\]= 1.1A


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