A) 25
B) 35
C) 45
D) None of these
Correct Answer: A
Solution :
Putting \[n=1\] in \[{{7}^{2n}}+{{2}^{3n-3}}{{.3}^{n-1}}\] then, \[{{7}^{2\times 1}}+{{2}^{3\times 1-3}}{{.3}^{1-1}}\] = \[{{7}^{2}}+{{2}^{0}}{{.3}^{0}}=49+1=50\] ......(i) Also, \[n=2\] \[{{7}^{2\times 2}}+{{2}^{3\times 2-3}}{{.3}^{2-1}}\]= \[2401+24=2425\] ......(ii) From (i) and (ii) it is always divisible by 25.
You need to login to perform this action.
You will be redirected in
3 sec
