A) 94
B) \[\text{+ and }\!\!\times\!\!\text{ ,4 and 6}\]
C) \[\text{+ and }\!\!\times\!\!\text{ ,4 and 6}\]
D) \[4+12=16\]
Correct Answer: A
Solution :
The rule is: Divide each number by 3 and write the quotients in the reverse order. \[8\div 10-3+5\times 6=8\] \[6\times 2+3\div 12-3==15\] \[3\div 7-5\times 10+3=10\] \[=15\times 5+5-20+10\]\[=15\times 5+5-2=75+5-2=78\] \[=8+10\times 3\div 5-6\] etc. \[=8+10\times 3\times \frac{1}{5}-6=8+6-6=8\] \[(3\div 4)+2=2\]\[+\]94.You need to login to perform this action.
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