Direction: In each of the following questions, which one of the four interchanges/replacing of signs as well as in numbers in left hand side would make the given equation correct? |
A) \[\div \,and\text{ }\times \], 2 and 3
B) \[\times \] to -, 2 and 6
C) \[\div \text{ }and\times \], 2 and 6
D) \[\times \] to -, 2 and 3
Correct Answer: D
Solution :
: After replacing, we get \[\left( 6\div 3 \right)-2=0\Rightarrow 2-2=0\]You need to login to perform this action.
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