A) \[a\,\phi \,\Delta \,b\]
B) \[b<a\times c\]
C) \[a<b+c\]
D) \[b<a\,\phi \,c\]
Correct Answer: C
Solution :
Using the usual notations, we have (a) The statement is \[a>b<c\Rightarrow a=c<b,\]which is false \[[\because c<b]\] (b) The statement is \[a>b<c\Rightarrow b<a>c,\]which is false. \[[\because b<a]\] (c) The statement is \[a>b<c\Rightarrow a<b>c,\]which is true (d) The statement is \[a>b<c\Rightarrow c<b<a,\]which is false. \[[\because b<a]\]You need to login to perform this action.
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