A) \[2A\delta 3C\]
B) \[6C\eta B~\]
C) \[B\delta 6A~\]
D) \[2A\eta 3C\]
Correct Answer: A
Solution :
: \[2A\delta B\Rightarrow 2A\cancel{=}B\] and \[B\beta 3C\Rightarrow B=3C\] \[\Rightarrow 2A\ne 3C\Rightarrow 2A\delta 3C.\]You need to login to perform this action.
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