A) ? 1
B) 0
C) \[\frac{1}{2}\]
D) 1
Correct Answer: C
Solution :
Let the number is x, then \[y=x-{{x}^{2}}\] Þ \[\frac{dy}{dx}=1-2x\] and \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=-2(<0)\] Þ \[1-2x=0\Rightarrow x=\frac{1}{2}\].
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